Problem 44943. Calculate Amount of Cake Frosting

Created by Pooja Lalan

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15342 Solutions
6460 Solvers

Last Solution submitted on Sep 24, 2020

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Alessandro A on 14 Feb 2020

This problem is yummy! :-)

Rafael S.T. Vieira on 2 Jun 2020

Simple & interesting.

Ghofran AL-NABELSI on 14 Jun 2020

The same as the surface area of a cylinder but without calculating the area of the bottom surface (circle) of the cylinder:
Original: A=2πrh+2πr2
Modified: A=2πrh+πr2

Weihua Huang on 22 Jun 2020

Having finished all 15 problem just to see what is the leading solution looks like. Then I realize smaller size doesn't mean the solution is better, often it is at the price of understand-ability.
Remember, in most cases, you write program for humans not for machines.

suyog choudhari on 8 Aug 2020

SA = ((2*pi*r*h)+(2*pi*(r^2)))-(pi*(r^2));

Solution Comments

Solution 2626153

1 Comment

1 Comment

Priya Narayan on 29 Jun 2020

calculating surface area except the base area

Solution 2502182

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1 Comment

bowen sui on 9 Jun 2020

easy

Solution 2477813

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1 Comment

Mateus Cruz on 5 Jun 2020

I do not think this exercise is correct. As one should not put frosting below the cake, the area of the cake to put frost on is the area of the circle on top of it plus the area of the "bent" rectangle on its sides. Thus:
function SA = func_frosting2(r,h)
ARectangle = pi*r*h;
ACircle = pi*r^2;
SA = ARectangle + ACircle;

I think the current solution is misleading

Solution 2458598

1 Comment

1 Comment

Rafael S.T. Vieira on 2 Jun 2020

simple and fun.

Solution 2244202

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1 Comment

srisai vangara on 29 Apr 2020

just tricky one.

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basic matlab

Problem 44943. Calculate Amount of Cake Frosting

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Problem 44943. Calculate Amount of Cake Frosting

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