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Question


second order differential equation are arranged in ring
mi (d^tδi/dt^2) + di(dδi/dt) = pmi − b sin(δi) − bint [sin(δi − δi+1) + sin(δi − δi−1)] where mi=1,di=0.3,b=1,bint=100,pmi=0.95...

8 years ago | 1 answer | 1

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