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Question
How can I take a symbolic triple integral of a piecewise function with a singularity at 10.7 that does not allow the value to surpass this value?
clc; clear; Pr=1; R0plus = input('Enter a value for R0+: '); syms yplus Yplus Yp; rplus = R0plus-yplus; Eoverv = piecewise...
7 years ago | 0 answers | 0
0
answersQuestion
How can I evaluate the double integral of a piece-wise function and get a numerical answer, instead of the rewritten integral?
pieclc; clear; R0plus = input('Entera value for R0+');%%Might have to change to syms%%% syms yplus; rplus = R0plus-yplus; k...
7 years ago | 2 answers | 0