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Manjunath Mulinti


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Converged to an infeasible point. fmincon stopped because the size of the current step is less than the default value of the step size tolerance but constraints are not satisfied to within the default value of the constraint tolerance.
N = 2; % Number of mass points X0 = rand(1,N); p0 = ones(1,N)/N; x0 = [X0 p0]; n = 1; lb = zeros(length(x0),1); ub = ones(...

7 years ago | 1 answer | 0

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Solver stopped prematurely. fmincon stopped because it exceeded the function evaluation limit, options.MaxFunctionEvaluations = 3000 (the default value).
x = [0.4,.8,.9,.8,0.84,.18,.19,.28,.66,.58,.87,.18,.69,.28,0.4,.38,.5,.1,.2,.4,.5,.99,.82,.5,.6,.3,.4,.2,.4,.59]; n = length(x)...

7 years ago | 0 answers | 0

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Converged to an infeasible point. fmincon stopped because the size of the current step is less than the default value of the step size tolerance but constraints are not satisfied to within the default value of the constraint tolerance.
X0 = rand(2,1); p0 = ones(2,1) / 2; x0 = [X0;p0]; n = 2 lb = zeros(length(x0),1) ub = ones(length(x0),1) Aeq = [zeros(1,le...

7 years ago | 0 answers | 0

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Row dimension of Aeq is inconsistent with length of beq.
x = [0.3,.5,.6] n = 3 lb = zeros(length(x),1) ub = ones(length(x),1) Aeq = [zeros(1,n); ones(1,n)] beq = 1 x = fm...

7 years ago | 1 answer | 0

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