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Aman Pratap Singh


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Answered
finding root using false position method
clc % Setting x as symbolic variable syms x; % Input Section y = input('Enter non-linear equations: '); a = input('Ente...

4 years ago | 0

Answered
Bisection Method Code Mathlab
f = @(x)('x^3-2x-5'); a = 2; b = 3; eps = 0.001; m = (a+b)/2; fprintf('\nThe value of, after bisection method, m is %f\n',...

4 years ago | 0