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명규 김


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butterworth 필터 적용시 신호 발산
X = data_signal; Fs = 32768; %data_signal의 sampling 주파수 n = 6; %butterworth 필터 차수 wn = 5; %cut off frequency Fn = Fs/2; %N...

1 year ago | 1 answer | 0

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변수 x에 대한 정적분이 시간이 너무 오래걸립니다. 해결할 수 있는 방법이 없을까요?
omega = [1:1:500] syms x d_x = 1 + (1 - 0).*x./1; k_x = d_x.*sqrt(omega)./2; sigma_x = pi.*(d_x./2).^2; taper = 1./sigma...

3 years ago | 1 answer | 0

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