Aurora

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Metodo di collocazione non lineare per risolvere problemi differenziali
il problema è il seguente -y''+e^-x yy'=e^x (x^2-2) y(-1)=-1/e y(1)=e sol y=xe^x Non mi sembra di aver sbagliato niente...

9 months ago | 1 answer | 0

1

answer

Question

Energy method with base is based by piecewise linear functions
The differential problem is: -(x^2 y')'+6y=8x+1/x y(-2)-2y'(-2)=-4 y(-1/2)=-5/4 The output isn't little different in te po...

9 months ago | 0 answers | 0

0

answers

Question

Energy method with Hermite cubic function (2 essential condition)
The different proble is: -(x^2 y')'+20y=7*x^2 -5 y(-1)=0 y(1)=0 sol: y=(x^2)/2-(x^4)/4-1/4 The next code has the following ...

9 months ago | 1 answer | 0

1

answer