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三个自变量，一个因变量如何拟合公式？(函数形式未知)。
用1stOpt帮楼主找了一个，有时间自己慢慢试还会有更好的结果： y = (x1^p1)*((1+p2*x3)/(p3+p4*x3))+p5+p6/x2 对应关系： 自变量x 自变量y 自变量z 因变量h...
3 years ago | 0
| accepted
