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果博东方开户代理【gb9905 .com】


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关于含有最值函数图形的实现。
下面是自己编的。希望各位大神帮忙修改一下,谢谢 i=1; for x=0:0.01:2/9 c=max[(2+3*x)/9,1/9+x,(1-x)/3]; y(1,i)=min[1-log(1-2*x)/log(3),-log(x)/...

3 years ago | 1 answer | 0

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