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极坐标作图的问题。
这种可以不用循环体，直接用向量来处理。 更多的代码可参考 《视觉大数据智能分析算法实战》[刘衍琦等] clc; clear all; close all; th=[1:100]*pi/10; r=repmat([0 1], 1, 50); po...
3 years ago | 0
| accepted
