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Question
矩阵的符号运算结果如何简化？。
syms EI l a EA = 1/2*EI; k = [EA/EI 0 0 -EA/EI 0 0;0 12/l^2 -6 0 -12/l^2 -6/l;0 -6/l 4 0 6/l 2;-EA/EI 0 0 EA/EI 0 0;0 -12/l^2 ...
3 years ago | 1 answer | 0
