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Question
余弦累加函数作图问题。
a=-pi/4:pi/999:pi/4; n=2:2:1000; y1=0.3/sum((cos(n.*(pi/9))./((n.^2-1).^2))).*sum(cos(n.*(pi/9)).*cos(n.*a)./((n.^2-1).^2)); ...
2 years ago | 1 answer | 0
