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Answered
Recursive relation
If I assume y(x)= sum(xk y^k), then dy/dx = k sum(xk * y^{k-1}) and y²(x) = sum ( sum (y(k-l)*y(l))) * x^k, the first sum being...

13 years ago | 0

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Recursive relation
Hi, I'ld like to plot the solution of dy/dx - y² = -exp(-x) on MATLAB. I assumed the solution was in the form of a Taylor se...

13 years ago | 4 answers | 0

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