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Wan Nurhanani


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Question


I need to find an inverse function of my equation. However, the output shows a RootOf in the equation. How can I get the inverse of my equation?
syms x a b h1 h2 l y=(h2*(x - b*x)^3)/3 - (a^3*h2*x^3)/3 + (a^4*h1*x^4)/4 - (a^3*x^3*(h1 - h2))/4 + (b*h2*x^3*(3*b^2 - 8*...

12 years ago | 1 answer | 0

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