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Question
Solve 1-(0.955.^n)-(0.005.^n)*(0.995.^(n-1))*n-(0.005.^2)*(0.995.^(n-2))*n*((n-1)/2)= 1/2 numerically with matlab
fh = @(n) 1-(0.955.^n)-(0.005.^n)*(0.995.^(n-1))*n-(0.005.^2)*(0.995.^(n-2))*n*((n-1)/2)- 0.5; n_solved = fsolve(@fh, n_gues...
10 years ago | 2 answers | 0
