I need help creating a loop.

Our teacher asked us to create a loop that calculates sin(x) to nth number of terms.

our professor obviously doesnt know how to use matlab because he has not helped us at all.

can someone help with this? i want to learn and comprehend what is going on?

-sin(x) = x-(x^3/3!)+(x^5/5!)-(x^7/7!
-The calculation should stop when the magnitude of the last terms is less than .0000006, it should work for positive and negative values
-The function should return the estimate and number of terms required to get this accuracy

After___terms sin(__) is approximated to be_____.

[C.J. Harris]

"our teacher asked us..."

So what have you done so far?

[Azzi Abdelmalek]

What have you done so far?

[Mark]

I have tried a few different things, and none of them seem to work, and I am getting lost in some of the code. I would just lke a push in the right direction. My math skills are pretty sharp and I have figured most of this out on my own. I just dont know where to begin on this problem. There seem to be too many variables for me to sort through. I do not want an answer. Only guidance.

Thanks mark mark

Answer 1

[Image Analyst]

Here's a hint

x = 1.234; % Whatever...
theSum = 0;
for term = 1 : 10000
  thisTerm = ...... % you do it.  Involves x and term.
  theSum = theSum + thisTerm;  % Accumulate
  if abs(thisTerm) < .0000006
    break;
  end
end
fprintf('The final sum = %f', theSum);

[Mark]

thank you. this makes sense, i will upload my formula when im done.

[Jan]

@Mark: It would be helpful if you post the solution.