It looks like [y;y']=[a,b] would mean y(0)=a and y'(0)=b, but a first order differential equation should have one initial condition y(t0)=y0.
Thanks Tim, yes, I did a mistake in the equation, its a 2nd order.
Back to basics 11 - Max Integer
Solve the set of simultaneous linear equations
MATCH THE STRINGS (2 CHAR) very easy
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