Solution Stats
Problem Comments
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27 Comments
Show
24 older comments
Oleg Komarov
on 26 Jan 2012
Not clear.
Giuseppe Cardillo
on 1 Feb 2012
What does it mean? It is not clear
Hristo Alexiev
on 1 Feb 2012
It's not understandable.
Aurelien Queffurust
on 3 Feb 2012
This problem is definitely not clear.
Martin
on 7 Feb 2012
Select the first, the third, the fifth, the seventh, ... element.
Sumit Agrawal
on 30 Mar 2013
nice problem
kurguz
on 6 Apr 2013
I cant understand this problem.
Maciej Kusper
on 4 Jun 2013
nice
Jon
on 13 Nov 2013
All solutions with score 10 or 11 use the regexp cheat.
L.K.R.Chaithanya kumar
on 15 Jul 2014
very good one
Miguel Maya
on 22 Feb 2015
I don't see why "x(1):2:length(x)" doesn't work, but "x(1:2:length(x))" does if it's the same thing?
It worked for me in MATLAB
Armando Femat
on 3 Dec 2015
Yes, you should change the redaction of the problem,maybe
Mir Rejaul Karim
on 16 Jul 2016
function y = everyOther(x)
for i=1:length(x)
if mod(x(i),2)~=0
y(i)=x(i)
end
end
y=y(y>0)
end
What's wrong with this solution?
Rong Zeng
on 21 Aug 2016
y = x(mod(x,2)==1);
it's not working, and i cant see why
Vineet Kumar
on 25 Aug 2016
nice problem
Jun Ren Tan
on 26 Dec 2016
y = x(1:2:length(x));?
SIVAPRAKASH DANABALASINGAM
on 10 Jan 2017
nice
Taha MRIHEEL
on 3 Apr 2017
good
Nikoo Azarm
on 6 Apr 2017
I can't understand, why is this wrong?
j=1;
for i=1:length(x)
if rem(x(i),2)~=0
y(j)=x(i);
j=j+1;
end
end
Barrie Cooper
on 25 Apr 2017
Nice problem, but I have been doing this with my son and it would be good if the exercises were more gently graduated with relevant syntax so he can learn without relying on his dad knowing Matlab!
James Tanner
on 26 Jun 2017
I can't believe someone solved this with size 9.
Gulen Insay
on 2 Sep 2017
The leading solution is not a solution. It just makes all the test assertions true.
Ghetto blaster
on 22 Oct 2018
Indexing is one of more important things in matlab and matrices. Gotta learn them good before heading on.
Banana
on 25 Sep 2019
Helo, hey hey ey
Matlab Expert
on 7 Mar 2020
Indexing is one of more important things in matlab and matrices. Gotta learn them good before heading on.
Simone Tiero
on 1 Nov 2020
Test suite suggests solution !
Qingyin Zhang
on 29 Nov 2020
y = x(1:2:end);
Solution Comments
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1 Comment
Cory Cunningham
on 11 Dec 2020
cool!
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1 Comment
XC_Wang
on 22 Oct 2020
this question is ambiguity...
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1 Comment
Marco Torres
on 7 Oct 2020
LOL, the solution is in the Test Suite :)
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1 Comment
天 夏
on 7 Oct 2020
why wrong?
My program woks!
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1 Comment
akarsh saxena
on 5 Oct 2020
error in template
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1 Comment
Tatjana Dulinskiene
on 2 Oct 2020
easy
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1 Comment
Piero Cimule
on 19 Jun 2020
y = x(1:2:length(x))
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1 Comment
swagata laxmi sengupta
on 17 May 2020
this was so easy
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1 Comment
Lewis Wootton
on 26 Mar 2020
why is it we cant just see a correct answer once we've submitted enough wrong answers? That would actually improve learning time as opposed to going round in circles not knowing what to do.
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1 Comment
Alessandro A
on 12 Feb 2020
Nice one!
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1 Comment
Sinh Luong
on 23 Oct 2019
Nice XU
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1 Comment
Sherlock Bugcrowd
on 7 Oct 2019
Great to solve
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1 Comment
Sherlock Bugcrowd
on 7 Oct 2019
Great to solve
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1 Comment
JIAN TANG
on 4 Oct 2019
How to view the leasing solution?
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2 Comments
Abuzar Qureshi
on 12 Sep 2019
Nice and Easy
Hoang Vu
on 22 Sep 2019
de dang va hay
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1 Comment
SJ Won
on 30 Jun 2019
Why doesn't this work??
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1 Comment
Bella A.
on 1 Mar 2019
nice!
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2 Comments
jljl jacky
on 4 Dec 2020
what is this code means?
Ralph Giffone
on 23 Dec 2020 at 23:02
This same exact code has been posted for numerous problems and is not a true solution. It appears to be a way of hacking the Test Suite into accepting the code as a correct solution. It is also concise, so it always appears to be the "leading" solution. (I have only checked a handful of "leading solutions", so this is a conjecture on my part.)
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1 Comment
Chuck Saunders
on 31 Jan 2018
The solution is given in the test suite!
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1 Comment
Dustin Jones
on 9 Jul 2017
works with numel(x) OR length(x)
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1 Comment
Norber245
on 22 Jun 2017
Great!,A pretty useful problem to solve!
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4 Comments
Show
1 older comment
Lily Clover
on 5 Jun 2017
Good job!
Mehedi hasan shuvo
on 6 Jun 2017
keep up
Rafael Hernandez-Walls
on 9 Jun 2017
nice
AJ Geiger
on 23 Jan 2018
Nice!
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2 Comments
SIVAPRAKASH DANABALASINGAM
on 10 Jan 2017
very easy
Sudhir Kumar
on 17 Oct 2018
please provide me the solution
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2 Comments
Devan Rao
on 10 Jan 2017
good
SIVAPRAKASH DANABALASINGAM
on 10 Jan 2017
nice
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2 Comments
sim yoke meng
on 21 Dec 2016
HAHAHAHA
SIVAPRAKASH DANABALASINGAM
on 10 Jan 2017
nice
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1 Comment
andreia3aral
on 9 Dec 2016
This solution is wrong. even if it is considered correct. This solution would eliminate elements with value equal to 0 as well.
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2 Comments
Daniel Fernandez
on 1 Sep 2016
I wrote:
function y = everyOther(x)
n=0;
for i=1:length(x)
if rem (i,2)==0
n=n+1
y(i-n)= x(i-1);
end
end
end
Could someone explain why it failed?
SIVAPRAKASH DANABALASINGAM
on 10 Jan 2017
nice
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2 Comments
Gaby
on 1 Sep 2016
You can improve it by doing: y = x(1:2:length(x));
SIVAPRAKASH DANABALASINGAM
on 10 Jan 2017
nice
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3 Comments
Rong Zeng
on 21 Aug 2016
y = x(mod(x,2)==1);
why is it not working? it works in matlab
SIVAPRAKASH DANABALASINGAM
on 10 Jan 2017
nice
XC_Wang
on 22 Oct 2020
I did the same thing...
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2 Comments
Peng Zhiyun
on 14 Aug 2015
Coding in my matlab2014 before submit is a good thicks.
SIVAPRAKASH DANABALASINGAM
on 10 Jan 2017
nice
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2 Comments
Jonathan Scott
on 24 Jul 2015
Still confused why my 'find' solution doesn't work
SIVAPRAKASH DANABALASINGAM
on 10 Jan 2017
nice
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2 Comments
Aarron Erbas
on 10 May 2015
Great i liked this
SIVAPRAKASH DANABALASINGAM
on 10 Jan 2017
nice
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3 Comments
Divakar Kittur
on 7 Nov 2014
Nice Job
SIVAPRAKASH DANABALASINGAM
on 10 Jan 2017
nice
DJHuang
on 2 Mar 2020
NICE JOB
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2 Comments
ABHILASH SINGH
on 5 Sep 2014
try to minimize the size
SIVAPRAKASH DANABALASINGAM
on 10 Jan 2017
nice
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2 Comments
Shreyas Shenoy
on 24 Jun 2014
Is this unfair?
SIVAPRAKASH DANABALASINGAM
on 10 Jan 2017
nice
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2 Comments
CHEONNO LEE
on 2 Feb 2014
vector concept is different with array.
SIVAPRAKASH DANABALASINGAM
on 10 Jan 2017
nice
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2 Comments
Max
on 18 Nov 2013
done
SIVAPRAKASH DANABALASINGAM
on 10 Jan 2017
nice
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2 Comments
Pawel Wojtas
on 18 Jan 2013
nice
Umair Nadeem
on 18 Nov 2013
good
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1 Comment
Rednas
on 3 Jan 2013
This problem is not clear to understand, you must return all the odd indexs.
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1 Comment
sea knowledge
on 11 Dec 2012
if you want concise code,use
y = x(1:2:ceil(end/2)*2-1)
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1 Comment
square seeker
on 19 Sep 2012
amazing problem
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1 Comment
Isktaine
on 8 Aug 2012
':' is superfluous but does mean it will work on matrices, not just vectors.
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